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From: BARILOCHENSE6999  (Original message) Sent: 26/07/2016 18:33
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From: BARILOCHENSE6999 Sent: 06/03/2020 17:45
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From: BARILOCHENSE6999 Sent: 06/03/2020 21:00
14 dic. 2019 - Subido por Rock In One
Exitos Rock Nacional Argentino - Las Mejores Canciones del Rock Argentino Vol.4 Exitos Rock Nacional ...

 
 

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From: BARILOCHENSE6999 Sent: 08/08/2020 17:11

3 Phi and Triangles

3.1 Phi and the Equilateral Triangle

equilateral+phiChris and Penny at Regina University's Math Central (Canada) show how we can use any circle to construct on it a hexagon and an equilateral triangle. Joining three pairs of points then reveals a line and its golden section point as follows:
  1. On any circle (centre O), construct the 6 equally spaced points A, B, C, D, E and F on its circumference without altering your compasses, so they are the same distance apart as the radius of the circle. ABCDEF forms a regular hexagon.
  2. Choose every other point to make an equilateral triangle ACE.
  3. On two of the sides of that triangle (AE and AC), mark their mid-points P and Q by joining the centre O to two of the unused points of the hexagon (F and B).
  4. The line PQ is then extended to meet the circle at point R.
    Q is the golden section point of the line PR.
hex and phiQ is a gold point of PR
The proof of this is left to you because it is a nice exercise either using coordinate geometry and the equation of the circle and the line PQ to find their point of intersection or else using plane geometry to find the lengths PR and QR.

The diagram on the left has many golden sections and yet contains only equilateral triangles. Can you make your own design based on this principle?

Chris and Penny's page shows how to continue using your compasses to make a pentagon with QR as one side. 

  •  Equilateral Triangles and the Golden ratio J F Rigby, Mathematical Gazette vol 72 (1988), pages 27-30.
http://www.maths.surrey.ac.uk/hosted-sites/R.Knott/Fibonacci/phi2DGeomTrig.html

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